# 单行子查询
# 单行操作符 = != <>不等于 > >= < <=
# 习题:查询公司大于149号员工工资的员工信息
SELECT employee_id,last_name,salary
FROM employees
WHERE salary > (
SELECT salary
FROM employees
WHERE employee_id=149
);
#习题:返回job_id与141号员工相同,salary比143号员工多的员工姓名,job_id和工资
SELECT last_name,job_id,salary
FROM employees
WHERE job_id = (
SELECT job_id
FROM employees
WHERE employee_id = 141
)
AND salary >= (
SELECT salary
FROM employees
WHERE employee_id=143
)
# 中英互换
# 习题:返回公司工资最少的员工的last_name,job-id和salary
SELECT last_name,job_id,salary
FROM employees
WHERE salary = (
SELECT MIN(salary)
FROM employees
)
/*
子查询编写技巧
1.从里往外写
2.从外往里写
*/
# 习题:查询与141号员工的manager-id
和department-id相同的其他的员工的employee_id,manager_id,department_id
# 方式一:
SELECT employee_id,manager_id,department_id
FROM employees
WHERE manager_id =(
SELECT manager_id
FROM employees
WHERE employee_id = 141
)
AND department_id = (
SELECT department_id
FROM employees
WHERE employee_id = 141
)
AND employee_id != 141;
#方式二:
SELECT employee_id,manager_id,department_id
FROM employees
WHERE (manager_id,department_id) = (
SELECT manager_id,department_id
FROM employees
WHERE employee_id = 141
)
AND employee_id != 141;
# 习题:查询最低工资大于110号部门最低工资的部门id和其最低工资
SELECT department_id,MIN(salary)
FROM employees
GROUP BY department_id
HAVING MIN(salary) > (
SELECT MIN(salary)
FROM employees
WHERE department_id = 110
);
#去空格
SELECT department_id,MIN(salary)
FROM employees
GROUP BY department_id
HAVING MIN(salary) > (
SELECT MIN(salary)
FROM employees
WHERE department_id = 60
)
SELECT department_id,MIN(salary)
FROM employees
GROUP BY department_id
HAVING MIN(salary) > (
SELECT MIN(salary)
FROM employees
WHERE department_id = 60
)
AND department_id IS NOT NULL;
SELECT department_id,MIN(salary)
FROM employees
WHERE department_id IS NOT NULL
GROUP BY department_id
HAVING MIN(salary) > (
SELECT MIN(salary)
FROM employees
WHERE department_id = 60
)
# 语法错误
SELECT department_id,MIN(salary)
FROM employees
GROUP BY department_id IS NOT NULL
HAVING MIN(salary) > (
SELECT MIN(salary)
FROM employees
WHERE department_id = 60
)
# 非法使用子查询
SELECT employee_id,last_name
FROM employees
WHERE salary = (
SELECT MIN(salary)
FROM employees
GROUP BY department_id;
)
# 查询的是准缺的数